Base | Representation |
---|---|
bin | 10100011111101101… |
… | …10011101111101001 |
3 | 1001101211220212210102 |
4 | 22033312303233221 |
5 | 140013340203301 |
6 | 5015505555145 |
7 | 536450506151 |
oct | 121766635751 |
9 | 31354825712 |
10 | 11003444201 |
11 | 4737180542 |
12 | 2171045ab5 |
13 | 1064862239 |
14 | 765529761 |
15 | 44601eb6b |
hex | 28fdb3be9 |
11003444201 has 4 divisors (see below), whose sum is σ = 11015934804. Its totient is φ = 10990953600.
The previous prime is 11003444197. The next prime is 11003444213. The reversal of 11003444201 is 10244430011.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 10244430011 = 211 ⋅48551801.
It can be written as a sum of positive squares in 2 ways, for example, as 3590406400 + 7413037801 = 59920^2 + 86099^2 .
It is a cyclic number.
It is not a de Polignac number, because 11003444201 - 22 = 11003444197 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11003444281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6243980 + ... + 6245741.
It is an arithmetic number, because the mean of its divisors is an integer number (2753983701).
Almost surely, 211003444201 is an apocalyptic number.
It is an amenable number.
11003444201 is a deficient number, since it is larger than the sum of its proper divisors (12490603).
11003444201 is an equidigital number, since it uses as much as digits as its factorization.
11003444201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12490602.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 11003444201 its reverse (10244430011), we get a palindrome (21247874212).
The spelling of 11003444201 in words is "eleven billion, three million, four hundred forty-four thousand, two hundred one".
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