11004063250945 has 4 divisors (see below), whose sum is σ = 13204875901140. Its totient is φ = 8803250600752.

The previous prime is 11004063250937. The next prime is 11004063250949. The reversal of 11004063250945 is 54905236040011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1417899851536 + 9586163399409 = 1190756^2 + 3096153^2 .

It is a cyclic number.

It is not a de Polignac number, because 11004063250945 - 2³ = 11004063250937 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11004063250898 and 11004063250907.

It is not an unprimeable number, because it can be changed into a prime (11004063250949) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100406325090 + ... + 1100406325099.

It is an arithmetic number, because the mean of its divisors is an integer number (3301218975285).

Almost surely, 2^{11004063250945} is an apocalyptic number.

It is an amenable number.

11004063250945 is a deficient number, since it is larger than the sum of its proper divisors (2200812650195).

11004063250945 is an equidigital number, since it uses as much as digits as its factorization.

11004063250945 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2200812650194.

The product of its (nonzero) digits is 129600, while the sum is 40.

Adding to 11004063250945 its reverse (54905236040011), we get a palindrome (65909299290956).

The spelling of 11004063250945 in words is "eleven trillion, four billion, sixty-three million, two hundred fifty thousand, nine hundred forty-five".