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11004120033 = 310663343997
BaseRepresentation
bin10100011111110010…
…11000101111100001
31001101220012012212020
422033321120233201
5140014023320113
65015532252053
7536456322414
oct121771305741
931356165766
1011004120033
1147375a2285
122171311029
131064a3aa3a
14765663b7b
15446105023
hex28fe58be1

11004120033 has 8 divisors (see below), whose sum is σ = 14673578688. Its totient is φ = 7335370704.

The previous prime is 11004120019. The next prime is 11004120037. The reversal of 11004120033 is 33002140011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11004120033 - 228 = 10735684577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11004119994 and 11004120021.

It is not an unprimeable number, because it can be changed into a prime (11004120037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 140010 + ... + 203987.

It is an arithmetic number, because the mean of its divisors is an integer number (1834197336).

Almost surely, 211004120033 is an apocalyptic number.

It is an amenable number.

11004120033 is a deficient number, since it is larger than the sum of its proper divisors (3669458655).

11004120033 is a wasteful number, since it uses less digits than its factorization.

11004120033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 354663.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 11004120033 its reverse (33002140011), we get a palindrome (44006260044).

The spelling of 11004120033 in words is "eleven billion, four million, one hundred twenty thousand, thirty-three".

Divisors: 1 3 10663 31989 343997 1031991 3668040011 11004120033