Base | Representation |
---|---|
bin | 10100011111110010… |
… | …11011011101010001 |
3 | 1001101220012210010002 |
4 | 22033321123131101 |
5 | 140014024144103 |
6 | 5015532415345 |
7 | 536456400011 |
oct | 121771333521 |
9 | 31356183102 |
10 | 11004131153 |
11 | 47375aa674 |
12 | 2171317555 |
13 | 1064a42b12 |
14 | 765667c41 |
15 | 446108488 |
hex | 28fe5b751 |
11004131153 has 4 divisors (see below), whose sum is σ = 11008266048. Its totient is φ = 10999996260.
The previous prime is 11004131111. The next prime is 11004131209. The reversal of 11004131153 is 35113140011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11004131153 - 214 = 11004114769 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11004131053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2063453 + ... + 2068778.
It is an arithmetic number, because the mean of its divisors is an integer number (2752066512).
Almost surely, 211004131153 is an apocalyptic number.
It is an amenable number.
11004131153 is a deficient number, since it is larger than the sum of its proper divisors (4134895).
11004131153 is an equidigital number, since it uses as much as digits as its factorization.
11004131153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4134894.
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 11004131153 its reverse (35113140011), we get a palindrome (46117271164).
The spelling of 11004131153 in words is "eleven billion, four million, one hundred thirty-one thousand, one hundred fifty-three".
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