11004134321 has 4 divisors (see below), whose sum is σ = 11004527652. Its totient is φ = 11003740992.

The previous prime is 11004134261. The next prime is 11004134333. The reversal of 11004134321 is 12343140011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 12343140011 = 1181 ⋅10451431.

It can be written as a sum of positive squares in 2 ways, for example, as 7495230625 + 3508903696 = 86575^2 + 59236^2 .

It is a cyclic number.

It is not a de Polignac number, because 11004134321 - 2¹⁸ = 11003872177 is a prime.

It is a super-2 number, since 2×11004134321² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11004134293 and 11004134302.

It is not an unprimeable number, because it can be changed into a prime (11004134341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151196 + ... + 211821.

It is an arithmetic number, because the mean of its divisors is an integer number (2751131913).

Almost surely, 2^11004134321 is an apocalyptic number.

It is an amenable number.

11004134321 is a deficient number, since it is larger than the sum of its proper divisors (393331).

11004134321 is an equidigital number, since it uses as much as digits as its factorization.

11004134321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 393330.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 11004134321 its reverse (12343140011), we get a palindrome (23347274332).

The spelling of 11004134321 in words is "eleven billion, four million, one hundred thirty-four thousand, three hundred twenty-one".