1100433401 has 4 divisors (see below), whose sum is σ = 1100500212. Its totient is φ = 1100366592.

The previous prime is 1100433379. The next prime is 1100433407. The reversal of 1100433401 is 1043340011.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 488365801 + 612067600 = 22099^2 + 24740^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100433401 - 2¹⁸ = 1100171257 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1100433401.

It is not an unprimeable number, because it can be changed into a prime (1100433407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10805 + ... + 48141.

It is an arithmetic number, because the mean of its divisors is an integer number (275125053).

Almost surely, 2^1100433401 is an apocalyptic number.

It is an amenable number.

1100433401 is a deficient number, since it is larger than the sum of its proper divisors (66811).

1100433401 is an equidigital number, since it uses as much as digits as its factorization.

1100433401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66810.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1100433401 is about 33172.7810260159. The cubic root of 1100433401 is about 1032.4156707563.

Adding to 1100433401 its reverse (1043340011), we get a palindrome (2143773412).

The spelling of 1100433401 in words is "one billion, one hundred million, four hundred thirty-three thousand, four hundred one".