Base | Representation |
---|---|
bin | 1010000000100010101101… |
… | …1001001001000101010011 |
3 | 1102222000100221102120100022 |
4 | 2200020223121021011103 |
5 | 2420244040130122233 |
6 | 35223211200214055 |
7 | 2214021065360423 |
oct | 240105331110523 |
9 | 42860327376308 |
10 | 11004434223443 |
11 | 3562a55263691 |
12 | 129889690a32b |
13 | 61a937caa4cb |
14 | 2a089043c483 |
15 | 1413b5b03398 |
hex | a022b649153 |
11004434223443 has 4 divisors (see below), whose sum is σ = 11005095922128. Its totient is φ = 11003772524760.
The previous prime is 11004434223421. The next prime is 11004434223509. The reversal of 11004434223443 is 34432243440011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11004434223443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11004434253443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 330824396 + ... + 330857657.
It is an arithmetic number, because the mean of its divisors is an integer number (2751273980532).
Almost surely, 211004434223443 is an apocalyptic number.
11004434223443 is a deficient number, since it is larger than the sum of its proper divisors (661698685).
11004434223443 is an equidigital number, since it uses as much as digits as its factorization.
11004434223443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 661698684.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 11004434223443 its reverse (34432243440011), we get a palindrome (45436677663454).
The spelling of 11004434223443 in words is "eleven trillion, four billion, four hundred thirty-four million, two hundred twenty-three thousand, four hundred forty-three".
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