110050601101131 has 4 divisors (see below), whose sum is σ = 146734134801512. Its totient is φ = 73367067400752.

The previous prime is 110050601101087. The next prime is 110050601101241. The reversal of 110050601101131 is 131101106050011.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 110050601101131 - 2¹⁵ = 110050601068363 is a prime.

It is a super-2 number, since 2×110050601101131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110050601101098 and 110050601101107.

It is not an unprimeable number, because it can be changed into a prime (110050601101531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18341766850186 + ... + 18341766850191.

It is an arithmetic number, because the mean of its divisors is an integer number (36683533700378).

Almost surely, 2^{110050601101131} is an apocalyptic number.

110050601101131 is a deficient number, since it is larger than the sum of its proper divisors (36683533700381).

110050601101131 is an equidigital number, since it uses as much as digits as its factorization.

110050601101131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36683533700380.

The product of its (nonzero) digits is 90, while the sum is 21.

Adding to 110050601101131 its reverse (131101106050011), we get a palindrome (241151707151142).

The spelling of 110050601101131 in words is "one hundred ten trillion, fifty billion, six hundred one million, one hundred one thousand, one hundred thirty-one".