Base | Representation |
---|---|
bin | 10100011111111011… |
… | …11001010101100001 |
3 | 1001101222102021100222 |
4 | 22033331321111201 |
5 | 140014324131423 |
6 | 5020013452425 |
7 | 536502344621 |
oct | 121775712541 |
9 | 31358367328 |
10 | 11005302113 |
11 | 473822a403 |
12 | 21717a1115 |
13 | 1065062ab0 |
14 | 765890881 |
15 | 44628a3c8 |
hex | 28ff79561 |
11005302113 has 16 divisors (see below), whose sum is σ = 12502721280. Its totient is φ = 9603183744.
The previous prime is 11005302109. The next prime is 11005302127. The reversal of 11005302113 is 31120350011.
It is a cyclic number.
It is not a de Polignac number, because 11005302113 - 22 = 11005302109 is a prime.
It is a super-2 number, since 2×110053021132 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11005302091 and 11005302100.
It is not an unprimeable number, because it can be changed into a prime (11005302103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 66245 + ... + 162477.
It is an arithmetic number, because the mean of its divisors is an integer number (781420080).
Almost surely, 211005302113 is an apocalyptic number.
11005302113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11005302113 is a deficient number, since it is larger than the sum of its proper divisors (1497419167).
11005302113 is a wasteful number, since it uses less digits than its factorization.
11005302113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96728.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 11005302113 its reverse (31120350011), we get a palindrome (42125652124).
The spelling of 11005302113 in words is "eleven billion, five million, three hundred two thousand, one hundred thirteen".
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