11005396843 has 4 divisors (see below), whose sum is σ = 12577596400. Its totient is φ = 9433197288.

The previous prime is 11005396793. The next prime is 11005396867. The reversal of 11005396843 is 34869350011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11005396843 - 2⁹ = 11005396331 is a prime.

It is a super-2 number, since 2×11005396843² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11005396796 and 11005396805.

It is not an unprimeable number, because it can be changed into a prime (11005396043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786099768 + ... + 786099781.

It is an arithmetic number, because the mean of its divisors is an integer number (3144399100).

Almost surely, 2^11005396843 is an apocalyptic number.

11005396843 is a deficient number, since it is larger than the sum of its proper divisors (1572199557).

11005396843 is an equidigital number, since it uses as much as digits as its factorization.

11005396843 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1572199556.

The product of its (nonzero) digits is 77760, while the sum is 40.

The spelling of 11005396843 in words is "eleven billion, five million, three hundred ninety-six thousand, eight hundred forty-three".