Base | Representation |
---|---|
bin | 110011001111111001… |
… | …0111011010110010001 |
3 | 101112001221002212010102 |
4 | 1212133302323112101 |
5 | 3300343102010113 |
6 | 122320354542145 |
7 | 10644161000051 |
oct | 1463762732621 |
9 | 345057085112 |
10 | 110055110033 |
11 | 427462710a0 |
12 | 193b5297955 |
13 | a4bba541ab |
14 | 548064b561 |
15 | 2ce1d81758 |
hex | 199fcbb591 |
110055110033 has 8 divisors (see below), whose sum is σ = 120074655360. Its totient is φ = 100037987280.
The previous prime is 110055109981. The next prime is 110055110069. The reversal of 110055110033 is 330011550011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 110055110033 - 28 = 110055109777 is a prime.
It is a super-2 number, since 2×1100551100332 (a number of 23 digits) contains 22 as substring.
It is a Curzon number.
It is a zygodrome in base 10.
It is a junction number, because it is equal to n+sod(n) for n = 110055109987 and 110055110014.
It is not an unprimeable number, because it can be changed into a prime (110055110233) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 509993 + ... + 692966.
It is an arithmetic number, because the mean of its divisors is an integer number (15009331920).
Almost surely, 2110055110033 is an apocalyptic number.
It is an amenable number.
110055110033 is a deficient number, since it is larger than the sum of its proper divisors (10019545327).
110055110033 is a wasteful number, since it uses less digits than its factorization.
110055110033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1211287.
The product of its (nonzero) digits is 225, while the sum is 20.
Adding to 110055110033 its reverse (330011550011), we get a palindrome (440066660044).
The spelling of 110055110033 in words is "one hundred ten billion, fifty-five million, one hundred ten thousand, thirty-three".
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