1100652143131 has 4 divisors (see below), whose sum is σ = 1116154286064. Its totient is φ = 1085150000200.

The previous prime is 1100652143119. The next prime is 1100652143159. The reversal of 1100652143131 is 1313412560011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100652143131 - 2⁹ = 1100652142619 is a prime.

It is a super-2 number, since 2×1100652143131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1100652143131.

It is not an unprimeable number, because it can be changed into a prime (1100652443131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7751071360 + ... + 7751071501.

It is an arithmetic number, because the mean of its divisors is an integer number (279038571516).

Almost surely, 2^{1100652143131} is an apocalyptic number.

1100652143131 is a deficient number, since it is larger than the sum of its proper divisors (15502142933).

1100652143131 is an equidigital number, since it uses as much as digits as its factorization.

1100652143131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15502142932.

The product of its (nonzero) digits is 2160, while the sum is 28.

The spelling of 1100652143131 in words is "one trillion, one hundred billion, six hundred fifty-two million, one hundred forty-three thousand, one hundred thirty-one".