110101121113 has 4 divisors (see below), whose sum is σ = 110362644388. Its totient is φ = 109839597840.

The previous prime is 110101121111. The next prime is 110101121153. The reversal of 110101121113 is 311121101011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311121101011 = 7 ⋅44445871573.

It can be written as a sum of positive squares in 2 ways, for example, as 1862095104 + 108239026009 = 43152^2 + 328997^2 .

It is a cyclic number.

It is not a de Polignac number, because 110101121113 - 2¹ = 110101121111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110101121093 and 110101121102.

It is not an unprimeable number, because it can be changed into a prime (110101121111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130761006 + ... + 130761847.

It is an arithmetic number, because the mean of its divisors is an integer number (27590661097).

Almost surely, 2^110101121113 is an apocalyptic number.

It is an amenable number.

110101121113 is a deficient number, since it is larger than the sum of its proper divisors (261523275).

110101121113 is an equidigital number, since it uses as much as digits as its factorization.

110101121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 261523274.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 110101121113 its reverse (311121101011), we get a palindrome (421222222124).

The spelling of 110101121113 in words is "one hundred ten billion, one hundred one million, one hundred twenty-one thousand, one hundred thirteen".