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11010212122003 = 67164331524209
BaseRepresentation
bin1010000000111000001111…
…0010000100110110010011
31102222120021121120020010021
42200032003302010312103
52420342403300401003
635230004400444311
72214314214610633
oct240160362046623
942876247506107
1011010212122003
11356544a786366
121299a29919697
1361b3490511b3
142a0c7b9546c3
15141602eb82bd
hexa0383c84d93

11010212122003 has 4 divisors (see below), whose sum is σ = 11174543646280. Its totient is φ = 10845880597728.

The previous prime is 11010212121983. The next prime is 11010212122123. The reversal of 11010212122003 is 30022121201011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11010212122003 - 217 = 11010211990931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11010212122703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82165762038 + ... + 82165762171.

It is an arithmetic number, because the mean of its divisors is an integer number (2793635911570).

Almost surely, 211010212122003 is an apocalyptic number.

11010212122003 is a deficient number, since it is larger than the sum of its proper divisors (164331524277).

11010212122003 is an equidigital number, since it uses as much as digits as its factorization.

11010212122003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 164331524276.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11010212122003 its reverse (30022121201011), we get a palindrome (41032333323014).

The spelling of 11010212122003 in words is "eleven trillion, ten billion, two hundred twelve million, one hundred twenty-two thousand, three".

Divisors: 1 67 164331524209 11010212122003