Base | Representation |
---|---|
bin | 11001000010010101111010… |
… | …100101111011010100100011 |
3 | 112102212121122220012011101012 |
4 | 121002111322211323110203 |
5 | 103413034122113031321 |
6 | 1030104452110131135 |
7 | 32123224212222605 |
oct | 3102257245732443 |
9 | 472777586164335 |
10 | 110112133330211 |
11 | 320a3325713921 |
12 | 104245767b0aab |
13 | 49596b6758c1c |
14 | 1d296545a9175 |
15 | cae408c5805b |
hex | 64257a97b523 |
110112133330211 has 4 divisors (see below), whose sum is σ = 110112188435424. Its totient is φ = 110112078225000.
The previous prime is 110112133330201. The next prime is 110112133330223. The reversal of 110112133330211 is 112033331211011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110112133330211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (110112133330201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24437915 + ... + 28590836.
It is an arithmetic number, because the mean of its divisors is an integer number (27528047108856).
Almost surely, 2110112133330211 is an apocalyptic number.
110112133330211 is a deficient number, since it is larger than the sum of its proper divisors (55105213).
110112133330211 is an equidigital number, since it uses as much as digits as its factorization.
110112133330211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55105212.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 110112133330211 its reverse (112033331211011), we get a palindrome (222145464541222).
The spelling of 110112133330211 in words is "one hundred ten trillion, one hundred twelve billion, one hundred thirty-three million, three hundred thirty thousand, two hundred eleven".
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