Base | Representation |
---|---|
bin | 11001000010010110110100… |
… | …011001000000001111001011 |
3 | 112102212201011110211120001222 |
4 | 121002112310121000033023 |
5 | 103413043113333133003 |
6 | 1030105132230032255 |
7 | 32123260225366505 |
oct | 3102266431001713 |
9 | 472781143746058 |
10 | 110113103021003 |
11 | 320a3783015975 |
12 | 104247a74a868b |
13 | 495980c613464 |
14 | 1d297072a6d75 |
15 | cae463e4dc38 |
hex | 6425b46403cb |
110113103021003 has 4 divisors (see below), whose sum is σ = 111979426801080. Its totient is φ = 108246779240928.
The previous prime is 110113103020997. The next prime is 110113103021041. The reversal of 110113103021003 is 300120301311011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 110113103021003 - 28 = 110113103020747 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (110113103021063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 933161889950 + ... + 933161890067.
It is an arithmetic number, because the mean of its divisors is an integer number (27994856700270).
Almost surely, 2110113103021003 is an apocalyptic number.
110113103021003 is a deficient number, since it is larger than the sum of its proper divisors (1866323780077).
110113103021003 is an equidigital number, since it uses as much as digits as its factorization.
110113103021003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1866323780076.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 110113103021003 its reverse (300120301311011), we get a palindrome (410233404332014).
The spelling of 110113103021003 in words is "one hundred ten trillion, one hundred thirteen billion, one hundred three million, twenty-one thousand, three".
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