11012101120121 has 4 divisors (see below), whose sum is σ = 11367330188544. Its totient is φ = 10656872051700.

The previous prime is 11012101120109. The next prime is 11012101120169. The reversal of 11012101120121 is 12102110121011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11012101120121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11012101120096 and 11012101120105.

It is not an unprimeable number, because it can be changed into a prime (11012101120171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177614534165 + ... + 177614534226.

It is an arithmetic number, because the mean of its divisors is an integer number (2841832547136).

Almost surely, 2^{11012101120121} is an apocalyptic number.

It is an amenable number.

11012101120121 is a deficient number, since it is larger than the sum of its proper divisors (355229068423).

11012101120121 is an equidigital number, since it uses as much as digits as its factorization.

11012101120121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 355229068422.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 11012101120121 its reverse (12102110121011), we get a palindrome (23114211241132).

The spelling of 11012101120121 in words is "eleven trillion, twelve billion, one hundred one million, one hundred twenty thousand, one hundred twenty-one".