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110121121113 = 3231595958277
BaseRepresentation
bin110011010001110111…
…0101111010101011001
3101112020112022120022020
41212203232233111121
53301012001333423
6122331113445053
710645622041143
oct1464356572531
9345215276266
10110121121113
114277a558203
1219413410789
13a4cc6271c3
145489311c93
152ce7a704e3
hex19a3baf559

110121121113 has 8 divisors (see below), whose sum is σ = 153211994688. Its totient is φ = 70222164144.

The previous prime is 110121121109. The next prime is 110121121147. The reversal of 110121121113 is 311121121011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 110121121113 - 22 = 110121121109 is a prime.

It is a super-2 number, since 2×1101211211132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110121121092 and 110121121101.

It is not an unprimeable number, because it can be changed into a prime (110121121163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 797979070 + ... + 797979207.

It is an arithmetic number, because the mean of its divisors is an integer number (19151499336).

Almost surely, 2110121121113 is an apocalyptic number.

It is an amenable number.

110121121113 is a deficient number, since it is larger than the sum of its proper divisors (43090873575).

110121121113 is a wasteful number, since it uses less digits than its factorization.

110121121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1595958303.

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 110121121113 its reverse (311121121011), we get a palindrome (421242242124).

The spelling of 110121121113 in words is "one hundred ten billion, one hundred twenty-one million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 3 23 69 1595958277 4787874831 36707040371 110121121113