Base | Representation |
---|---|
bin | 10000000001100101010… |
… | …110011111100101011011 |
3 | 10220021102100200220220100 |
4 | 100001211112133211123 |
5 | 121020240234220011 |
6 | 2201520111230443 |
7 | 142363026516453 |
oct | 20014526374533 |
9 | 3807370626810 |
10 | 1101212023131 |
11 | 395026529a00 |
12 | 159509818423 |
13 | 7cac7c1c11c |
14 | 3b428446d63 |
15 | 1d9a20b3d56 |
hex | 1006559f95b |
1101212023131 has 72 divisors (see below), whose sum is σ = 1762438860000. Its totient is φ = 662050033920.
The previous prime is 1101212023081. The next prime is 1101212023151. The reversal of 1101212023131 is 1313202121011.
It is not a de Polignac number, because 1101212023131 - 211 = 1101212021083 is a prime.
It is a super-2 number, since 2×11012120231312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1101212023151) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 136132935 + ... + 136141023.
It is an arithmetic number, because the mean of its divisors is an integer number (24478317500).
Almost surely, 21101212023131 is an apocalyptic number.
1101212023131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1101212023131 is a deficient number, since it is larger than the sum of its proper divisors (661226836869).
1101212023131 is a wasteful number, since it uses less digits than its factorization.
1101212023131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9105 (or 9091 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 1101212023131 its reverse (1313202121011), we get a palindrome (2414414144142).
The spelling of 1101212023131 in words is "one trillion, one hundred one billion, two hundred twelve million, twenty-three thousand, one hundred thirty-one".
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