Base | Representation |
---|---|
bin | 1010000001000000000001… |
… | …1011110000001011010011 |
3 | 1102222202200100201021121202 |
4 | 2200100000123300023103 |
5 | 2420411144134002123 |
6 | 35230552104341415 |
7 | 2214420100431641 |
oct | 240200033601323 |
9 | 42882610637552 |
10 | 11012303422163 |
11 | 35663232120aa |
12 | 129a31217486b |
13 | 61b5c03b4204 |
14 | 2a0dd95b8191 |
15 | 1416c68b2a28 |
hex | a04006f02d3 |
11012303422163 has 4 divisors (see below), whose sum is σ = 11013488442048. Its totient is φ = 11011118402280.
The previous prime is 11012303422121. The next prime is 11012303422181. The reversal of 11012303422163 is 36122430321011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11012303422163 - 222 = 11012299227859 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11012303442163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 592496003 + ... + 592514588.
It is an arithmetic number, because the mean of its divisors is an integer number (2753372110512).
Almost surely, 211012303422163 is an apocalyptic number.
11012303422163 is a deficient number, since it is larger than the sum of its proper divisors (1185019885).
11012303422163 is an equidigital number, since it uses as much as digits as its factorization.
11012303422163 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1185019884.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 11012303422163 its reverse (36122430321011), we get a palindrome (47134733743174).
The spelling of 11012303422163 in words is "eleven trillion, twelve billion, three hundred three million, four hundred twenty-two thousand, one hundred sixty-three".
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