11012322113 has 4 divisors (see below), whose sum is σ = 11859423828. Its totient is φ = 10165220400.

The previous prime is 11012322109. The next prime is 11012322127. The reversal of 11012322113 is 31122321011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31122321011 = 23131 ⋅1345481.

It can be written as a sum of positive squares in 2 ways, for example, as 7614831169 + 3397490944 = 87263^2 + 58288^2 .

It is a cyclic number.

It is not a de Polignac number, because 11012322113 - 2² = 11012322109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11012322091 and 11012322100.

It is not an unprimeable number, because it can be changed into a prime (11012322413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 423550838 + ... + 423550863.

It is an arithmetic number, because the mean of its divisors is an integer number (2964855957).

Almost surely, 2^11012322113 is an apocalyptic number.

11012322113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11012322113 is a deficient number, since it is larger than the sum of its proper divisors (847101715).

11012322113 is an equidigital number, since it uses as much as digits as its factorization.

11012322113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 847101714.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11012322113 its reverse (31122321011), we get a palindrome (42134643124).

The spelling of 11012322113 in words is "eleven billion, twelve million, three hundred twenty-two thousand, one hundred thirteen".