11012333131 has 4 divisors (see below), whose sum is σ = 11280926664. Its totient is φ = 10743739600.

The previous prime is 11012333119. The next prime is 11012333141. The reversal of 11012333131 is 13133321011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11012333131 - 2⁵ = 11012333099 is a prime.

It is a super-2 number, since 2×11012333131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11012333099 and 11012333108.

It is not an unprimeable number, because it can be changed into a prime (11012333141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134296705 + ... + 134296786.

It is an arithmetic number, because the mean of its divisors is an integer number (2820231666).

Almost surely, 2^11012333131 is an apocalyptic number.

11012333131 is a deficient number, since it is larger than the sum of its proper divisors (268593533).

11012333131 is an equidigital number, since it uses as much as digits as its factorization.

11012333131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 268593532.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11012333131 its reverse (13133321011), we get a palindrome (24145654142).

The spelling of 11012333131 in words is "eleven billion, twelve million, three hundred thirty-three thousand, one hundred thirty-one".