11012443140433 has 8 divisors (see below), whose sum is σ = 13132851447168. Its totient is φ = 9028835369664.

The previous prime is 11012443140427. The next prime is 11012443140451. The reversal of 11012443140433 is 33404134421011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11012443140433 - 2¹³ = 11012443132241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11012443140395 and 11012443140404.

It is not an unprimeable number, because it can be changed into a prime (11012443140493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34200133816 + ... + 34200134137.

It is an arithmetic number, because the mean of its divisors is an integer number (1641606430896).

Almost surely, 2^{11012443140433} is an apocalyptic number.

It is an amenable number.

11012443140433 is a deficient number, since it is larger than the sum of its proper divisors (2120408306735).

11012443140433 is an equidigital number, since it uses as much as digits as its factorization.

11012443140433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68400267983.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 11012443140433 its reverse (33404134421011), we get a palindrome (44416577561444).

The spelling of 11012443140433 in words is "eleven trillion, twelve billion, four hundred forty-three million, one hundred forty thousand, four hundred thirty-three".