11013013130113 has 4 divisors (see below), whose sum is σ = 11491839787968. Its totient is φ = 10534186472260.

The previous prime is 11013013130081. The next prime is 11013013130191. The reversal of 11013013130113 is 31103131031011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11013013130113 - 2⁵ = 11013013130081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11013013130213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 239413328893 + ... + 239413328938.

It is an arithmetic number, because the mean of its divisors is an integer number (2872959946992).

Almost surely, 2^{11013013130113} is an apocalyptic number.

It is an amenable number.

11013013130113 is a deficient number, since it is larger than the sum of its proper divisors (478826657855).

11013013130113 is an equidigital number, since it uses as much as digits as its factorization.

11013013130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 478826657854.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 11013013130113 its reverse (31103131031011), we get a palindrome (42116144161124).

The spelling of 11013013130113 in words is "eleven trillion, thirteen billion, thirteen million, one hundred thirty thousand, one hundred thirteen".