1101302011113 has 4 divisors (see below), whose sum is σ = 1468402681488. Its totient is φ = 734201340740.

The previous prime is 1101302011091. The next prime is 1101302011127. The reversal of 1101302011113 is 3111102031011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1101302011113 - 2¹⁰ = 1101302010089 is a prime.

It is a super-2 number, since 2×1101302011113² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1101302011092 and 1101302011101.

It is not an unprimeable number, because it can be changed into a prime (1101302011163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183550335183 + ... + 183550335188.

It is an arithmetic number, because the mean of its divisors is an integer number (367100670372).

Almost surely, 2^{1101302011113} is an apocalyptic number.

It is an amenable number.

1101302011113 is a deficient number, since it is larger than the sum of its proper divisors (367100670375).

1101302011113 is an equidigital number, since it uses as much as digits as its factorization.

1101302011113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 367100670374.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 1101302011113 its reverse (3111102031011), we get a palindrome (4212404042124).

The spelling of 1101302011113 in words is "one trillion, one hundred one billion, three hundred two million, eleven thousand, one hundred thirteen".