11013143403 has 4 divisors (see below), whose sum is σ = 14684191208. Its totient is φ = 7342095600.

The previous prime is 11013143399. The next prime is 11013143437. The reversal of 11013143403 is 30434131011.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 11013143403 - 2² = 11013143399 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11013143403.

It is not an unprimeable number, because it can be changed into a prime (11013143803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1835523898 + ... + 1835523903.

It is an arithmetic number, because the mean of its divisors is an integer number (3671047802).

Almost surely, 2^11013143403 is an apocalyptic number.

11013143403 is a deficient number, since it is larger than the sum of its proper divisors (3671047805).

11013143403 is an equidigital number, since it uses as much as digits as its factorization.

11013143403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3671047804.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11013143403 its reverse (30434131011), we get a palindrome (41447274414).

The spelling of 11013143403 in words is "eleven billion, thirteen million, one hundred forty-three thousand, four hundred three".