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1101322045435 = 51522391446833
BaseRepresentation
bin10000000001101011111…
…010001100011111111011
310220021201000201122010111
4100001223322030133323
5121021001420423220
62201535041325151
7142365533633263
oct20015372143773
93807630648114
101101322045435
11395082646327
1215953a6367b7
137cb14961691
143b438cc67a3
151d9aba9815a
hex1006be8c7fb

1101322045435 has 8 divisors (see below), whose sum is σ = 1321596048960. Its totient is φ = 881051240064.

The previous prime is 1101322045403. The next prime is 1101322045471. The reversal of 1101322045435 is 5345402231011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1101322045435 - 25 = 1101322045403 is a prime.

It is a super-2 number, since 2×11013220454352 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1101322045397 and 1101322045406.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37779 + ... + 1484611.

It is an arithmetic number, because the mean of its divisors is an integer number (165199506120).

Almost surely, 21101322045435 is an apocalyptic number.

1101322045435 is a deficient number, since it is larger than the sum of its proper divisors (220274003525).

1101322045435 is a wasteful number, since it uses less digits than its factorization.

1101322045435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1599077.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1101322045435 its reverse (5345402231011), we get a palindrome (6446724276446).

The spelling of 1101322045435 in words is "one trillion, one hundred one billion, three hundred twenty-two million, forty-five thousand, four hundred thirty-five".

Divisors: 1 5 152239 761195 1446833 7234165 220264409087 1101322045435