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11013244201 = 64317127907
BaseRepresentation
bin10100100000111000…
…01100010100101001
31001102112100202212101
422100130030110221
5140023342303301
65020500013401
7536630013451
oct122034142451
931375322771
1011013244201
114741764413
122174391261
1310668b3a5b
1476695ad61
15446d08701
hex29070c529

11013244201 has 4 divisors (see below), whose sum is σ = 11030372752. Its totient is φ = 10996115652.

The previous prime is 11013244199. The next prime is 11013244211. The reversal of 11013244201 is 10244231011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11013244201 - 21 = 11013244199 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11013244211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8563311 + ... + 8564596.

It is an arithmetic number, because the mean of its divisors is an integer number (2757593188).

Almost surely, 211013244201 is an apocalyptic number.

It is an amenable number.

11013244201 is a deficient number, since it is larger than the sum of its proper divisors (17128551).

11013244201 is an equidigital number, since it uses as much as digits as its factorization.

11013244201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17128550.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 11013244201 its reverse (10244231011), we get a palindrome (21257475212).

The spelling of 11013244201 in words is "eleven billion, thirteen million, two hundred forty-four thousand, two hundred one".

Divisors: 1 643 17127907 11013244201