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11013344331011 = 111001213121001
BaseRepresentation
bin1010000001000011111001…
…1110100000010100000011
31102222212100220100221010022
42200100332132200110003
52420420312122043021
635231243250524055
72214454640134421
oct240207636402403
942885326327108
1011013344331011
113566807837350
12129a56289662b
1361b727c457c9
142a1097934111
15141737e751ab
hexa043e7a0503

11013344331011 has 4 divisors (see below), whose sum is σ = 12014557452024. Its totient is φ = 10012131210000.

The previous prime is 11013344330993. The next prime is 11013344331029.

11013344331011 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (11013344330993) and next prime (11013344331029).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11013344331011 is a prime.

It is a super-2 number, since 2×110133443310112 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11013344331061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500606560490 + ... + 500606560511.

It is an arithmetic number, because the mean of its divisors is an integer number (3003639363006).

Almost surely, 211013344331011 is an apocalyptic number.

11013344331011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11013344331011 is a deficient number, since it is larger than the sum of its proper divisors (1001213121013).

11013344331011 is a wasteful number, since it uses less digits than its factorization.

11013344331011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1001213121012.

The product of its (nonzero) digits is 1296, while the sum is 26.

It can be divided in two parts, 1101334 and 4331011, that added together give a palindrome (5432345).

The spelling of 11013344331011 in words is "eleven trillion, thirteen billion, three hundred forty-four million, three hundred thirty-one thousand, eleven".

Divisors: 1 11 1001213121001 11013344331011