Base | Representation |
---|---|
bin | 11001000010110000111111… |
… | …110100010010011100000011 |
3 | 112102222101201102212011100112 |
4 | 121002300333310102130003 |
5 | 103414023200233311433 |
6 | 1030130101351141535 |
7 | 32125303624015451 |
oct | 3102607764223403 |
9 | 472871642764315 |
10 | 110141212010243 |
11 | 32104697893597 |
12 | 1042a1310748ab |
13 | 495c36bca147b |
14 | 1d2ac125079d1 |
15 | cb005ba43348 |
hex | 642c3fd12703 |
110141212010243 has 4 divisors (see below), whose sum is σ = 110141305486968. Its totient is φ = 110141118533520.
The previous prime is 110141212010087. The next prime is 110141212010327. The reversal of 110141212010243 is 342010212141011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 110141212010243 - 214 = 110141211993859 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (110141212015243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44948093 + ... + 47335118.
It is an arithmetic number, because the mean of its divisors is an integer number (27535326371742).
Almost surely, 2110141212010243 is an apocalyptic number.
110141212010243 is a deficient number, since it is larger than the sum of its proper divisors (93476725).
110141212010243 is an equidigital number, since it uses as much as digits as its factorization.
110141212010243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93476724.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 110141212010243 its reverse (342010212141011), we get a palindrome (452151424151254).
The spelling of 110141212010243 in words is "one hundred ten trillion, one hundred forty-one billion, two hundred twelve million, ten thousand, two hundred forty-three".
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