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1101412431433 = 1117986045149
BaseRepresentation
bin10000000001110001010…
…010111111011001001001
310220021221022210201102001
4100001301102333121021
5121021143040301213
62201552030511001
7142401012124306
oct20016122773111
93807838721361
101101412431433
113951196706a6
12159564965461
137cb2a5ba212
143b446cd40ad
151d9b499e1dd
hex100714bf649

1101412431433 has 4 divisors (see below), whose sum is σ = 1102398477700. Its totient is φ = 1100426385168.

The previous prime is 1101412431421. The next prime is 1101412431473. The reversal of 1101412431433 is 3341342141011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 472012969024 + 629399462409 = 687032^2 + 793347^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1101412431433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1101412431473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 493021458 + ... + 493023691.

It is an arithmetic number, because the mean of its divisors is an integer number (275599619425).

Almost surely, 21101412431433 is an apocalyptic number.

It is an amenable number.

1101412431433 is a deficient number, since it is larger than the sum of its proper divisors (986046267).

1101412431433 is an equidigital number, since it uses as much as digits as its factorization.

1101412431433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 986046266.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1101412431433 its reverse (3341342141011), we get a palindrome (4442754572444).

The spelling of 1101412431433 in words is "one trillion, one hundred one billion, four hundred twelve million, four hundred thirty-one thousand, four hundred thirty-three".

Divisors: 1 1117 986045149 1101412431433