Base | Representation |
---|---|
bin | 1010000001000111001000… |
… | …0100111011001011101011 |
3 | 1102222221121020100112100202 |
4 | 2200101302010323023223 |
5 | 2420424100232244210 |
6 | 35231505214022415 |
7 | 2214515251425101 |
oct | 240216204731353 |
9 | 42887536315322 |
10 | 11014210040555 |
11 | 3567111478787 |
12 | 129a7647a7a0b |
13 | 61b8353c4387 |
14 | 2a113a8c5c71 |
15 | 141788e7b9a5 |
hex | a047213b2eb |
11014210040555 has 16 divisors (see below), whose sum is σ = 13365837682560. Its totient is φ = 8712181750272.
The previous prime is 11014210040501. The next prime is 11014210040569. The reversal of 11014210040555 is 55504001241011.
It is a cyclic number.
It is not a de Polignac number, because 11014210040555 - 214 = 11014210024171 is a prime.
It is a super-3 number, since 3×110142100405553 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23498447 + ... + 23962583.
It is an arithmetic number, because the mean of its divisors is an integer number (835364855160).
Almost surely, 211014210040555 is an apocalyptic number.
11014210040555 is a deficient number, since it is larger than the sum of its proper divisors (2351627642005).
11014210040555 is an equidigital number, since it uses as much as digits as its factorization.
11014210040555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 517558.
The product of its (nonzero) digits is 4000, while the sum is 29.
Adding to 11014210040555 its reverse (55504001241011), we get a palindrome (66518211281566).
The spelling of 11014210040555 in words is "eleven trillion, fourteen billion, two hundred ten million, forty thousand, five hundred fifty-five".
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