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11014210040555 = 58953327464137
BaseRepresentation
bin1010000001000111001000…
…0100111011001011101011
31102222221121020100112100202
42200101302010323023223
52420424100232244210
635231505214022415
72214515251425101
oct240216204731353
942887536315322
1011014210040555
113567111478787
12129a7647a7a0b
1361b8353c4387
142a113a8c5c71
15141788e7b9a5
hexa047213b2eb

11014210040555 has 16 divisors (see below), whose sum is σ = 13365837682560. Its totient is φ = 8712181750272.

The previous prime is 11014210040501. The next prime is 11014210040569. The reversal of 11014210040555 is 55504001241011.

It is a cyclic number.

It is not a de Polignac number, because 11014210040555 - 214 = 11014210024171 is a prime.

It is a super-3 number, since 3×110142100405553 (a number of 40 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23498447 + ... + 23962583.

It is an arithmetic number, because the mean of its divisors is an integer number (835364855160).

Almost surely, 211014210040555 is an apocalyptic number.

11014210040555 is a deficient number, since it is larger than the sum of its proper divisors (2351627642005).

11014210040555 is an equidigital number, since it uses as much as digits as its factorization.

11014210040555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 517558.

The product of its (nonzero) digits is 4000, while the sum is 29.

Adding to 11014210040555 its reverse (55504001241011), we get a palindrome (66518211281566).

The spelling of 11014210040555 in words is "eleven trillion, fourteen billion, two hundred ten million, forty thousand, five hundred fifty-five".

Divisors: 1 5 89 445 53327 266635 464137 2320685 4746103 23730515 41308193 206540965 24751033799 123755168995 2202842008111 11014210040555