11014321450113 has 6 divisors (see below), whose sum is σ = 15909575427954. Its totient is φ = 7342880966736.

The previous prime is 11014321450091. The next prime is 11014321450127. The reversal of 11014321450113 is 31105412341011.

11014321450113 is a `hidden beast` number, since 1 + 1 + 0 + 143 + 2 + 1 + 4 + 501 + 13 = 666.

It can be written as a sum of positive squares in only one way, i.e., 6339956377329 + 4674365072784 = 2517927^2 + 2162028^2 .

It is a de Polignac number, because none of the positive numbers 2^k-11014321450113 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11014321450193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 611906747220 + ... + 611906747237.

It is an arithmetic number, because the mean of its divisors is an integer number (2651595904659).

Almost surely, 2^{11014321450113} is an apocalyptic number.

It is an amenable number.

11014321450113 is a deficient number, since it is larger than the sum of its proper divisors (4895253977841).

11014321450113 is a wasteful number, since it uses less digits than its factorization.

11014321450113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1223813494463 (or 1223813494460 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 11014321450113 its reverse (31105412341011), we get a palindrome (42119733791124).

The spelling of 11014321450113 in words is "eleven trillion, fourteen billion, three hundred twenty-one million, four hundred fifty thousand, one hundred thirteen".