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11014415147 = 42532589799
BaseRepresentation
bin10100100001000001…
…01010001100101011
31001102121120021002202
422100200222030223
5140024142241042
65020541050415
7536642661341
oct122040521453
931377507082
1011014415147
11474239413a
122174856a0b
131066c03a18
14766b83991
15446e8a632
hex29082a32b

11014415147 has 4 divisors (see below), whose sum is σ = 11017009200. Its totient is φ = 11011821096.

The previous prime is 11014415131. The next prime is 11014415171. The reversal of 11014415147 is 74151441011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11014415147 - 24 = 11014415131 is a prime.

It is a super-3 number, since 3×110144151473 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11014415117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1290647 + ... + 1299152.

It is an arithmetic number, because the mean of its divisors is an integer number (2754252300).

Almost surely, 211014415147 is an apocalyptic number.

11014415147 is a deficient number, since it is larger than the sum of its proper divisors (2594053).

11014415147 is an equidigital number, since it uses as much as digits as its factorization.

11014415147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2594052.

The product of its (nonzero) digits is 2240, while the sum is 29.

Adding to 11014415147 its reverse (74151441011), we get a palindrome (85165856158).

The spelling of 11014415147 in words is "eleven billion, fourteen million, four hundred fifteen thousand, one hundred forty-seven".

Divisors: 1 4253 2589799 11014415147