110203215113 has 4 divisors (see below), whose sum is σ = 113758157568. Its totient is φ = 106648272660.

The previous prime is 110203215107. The next prime is 110203215119. The reversal of 110203215113 is 311512302011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311512302011 = 32159 ⋅9686629.

It is an interprime number because it is at equal distance from previous prime (110203215107) and next prime (110203215119).

It is not a de Polignac number, because 110203215113 - 2¹⁰ = 110203214089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110203215119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1777471181 + ... + 1777471242.

It is an arithmetic number, because the mean of its divisors is an integer number (28439539392).

Almost surely, 2^110203215113 is an apocalyptic number.

It is an amenable number.

110203215113 is a deficient number, since it is larger than the sum of its proper divisors (3554942455).

110203215113 is an equidigital number, since it uses as much as digits as its factorization.

110203215113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3554942454.

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 110203215113 its reverse (311512302011), we get a palindrome (421715517124).

The spelling of 110203215113 in words is "one hundred ten billion, two hundred three million, two hundred fifteen thousand, one hundred thirteen".