Base | Representation |
---|---|
bin | 11001000011110010010010… |
… | …110000111010101001001011 |
3 | 112110020002200121021011012102 |
4 | 121003302102300322221023 |
5 | 103421200242204041021 |
6 | 1030222214411304015 |
7 | 32133335220366122 |
oct | 3103622260725113 |
9 | 473202617234172 |
10 | 110211323112011 |
11 | 321313a576a000 |
12 | 1043b83914b00b |
13 | 4965b634487c4 |
14 | 1d30383ba0ab9 |
15 | cb1cb1c9d00b |
hex | 643c92c3aa4b |
110211323112011 has 8 divisors (see below), whose sum is σ = 121224175084848. Its totient is φ = 100192111918800.
The previous prime is 110211323112001. The next prime is 110211323112061.
110211323112011 is nontrivially palindromic in base 10.
It is a de Polignac number, because none of the positive numbers 2k-110211323112011 is a prime.
It is not an unprimeable number, because it can be changed into a prime (110211323112001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41401697810 + ... + 41401700471.
It is an arithmetic number, because the mean of its divisors is an integer number (15153021885606).
Almost surely, 2110211323112011 is an apocalyptic number.
110211323112011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
110211323112011 is a deficient number, since it is larger than the sum of its proper divisors (11012851972837).
110211323112011 is an frugal number, since it uses more digits than its factorization.
110211323112011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82803398314 (or 82803398292 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 20.
The spelling of 110211323112011 in words is "one hundred ten trillion, two hundred eleven billion, three hundred twenty-three million, one hundred twelve thousand, eleven".
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