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1102121332003 = 10871013911069
BaseRepresentation
bin10000000010011011100…
…011001110110100100011
310220100202201201121011201
4100002123203032310203
5121024121030111003
62202150233022031
7142424410515646
oct20023343166443
93810681647151
101102121332003
1139545283a13a
12159722254917
137cc11424903
143b4b3107a5d
151da06d2db1d
hex1009b8ced23

1102121332003 has 4 divisors (see below), whose sum is σ = 1103135244160. Its totient is φ = 1101107419848.

The previous prime is 1102121331953. The next prime is 1102121332007. The reversal of 1102121332003 is 3002331212011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1102121332003 - 213 = 1102121323811 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1102121332007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 506954448 + ... + 506956621.

It is an arithmetic number, because the mean of its divisors is an integer number (275783811040).

Almost surely, 21102121332003 is an apocalyptic number.

1102121332003 is a deficient number, since it is larger than the sum of its proper divisors (1013912157).

1102121332003 is a wasteful number, since it uses less digits than its factorization.

1102121332003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1013912156.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1102121332003 its reverse (3002331212011), we get a palindrome (4104452544014).

The spelling of 1102121332003 in words is "one trillion, one hundred two billion, one hundred twenty-one million, three hundred thirty-two thousand, three".

Divisors: 1 1087 1013911069 1102121332003