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11021232012113 = 49158913381011
BaseRepresentation
bin1010000001100001010010…
…0111100111101101010001
31110000121201121102122110102
42200120110213213231101
52421032440343341423
635235030055142145
72215154255254301
oct240302447475521
943017647378412
1011021232012113
11356a095169964
12129bba4374955
1361c3b4120c2b
142a1605321601
15141a4a685c28
hexa06149e7b51

11021232012113 has 8 divisors (see below), whose sum is σ = 11043894956256. Its totient is φ = 10998569948800.

The previous prime is 11021232012097. The next prime is 11021232012173. The reversal of 11021232012113 is 31121023212011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11021232012113 - 24 = 11021232012097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11021232012173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28735778 + ... + 29116788.

It is an arithmetic number, because the mean of its divisors is an integer number (1380486869532).

Almost surely, 211021232012113 is an apocalyptic number.

It is an amenable number.

11021232012113 is a deficient number, since it is larger than the sum of its proper divisors (22662944143).

11021232012113 is an equidigital number, since it uses as much as digits as its factorization.

11021232012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 440415.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11021232012113 its reverse (31121023212011), we get a palindrome (42142255224124).

The spelling of 11021232012113 in words is "eleven trillion, twenty-one billion, two hundred thirty-two million, twelve thousand, one hundred thirteen".

Divisors: 1 491 58913 381011 28926283 187076401 22446501043 11021232012113