11021680993 has 4 divisors (see below), whose sum is σ = 11022092848. Its totient is φ = 11021269140.

The previous prime is 11021680979. The next prime is 11021681003. The reversal of 11021680993 is 39908612011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11021680993 - 2⁵ = 11021680961 is a prime.

It is a super-2 number, since 2×11021680993² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11021680913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162771 + ... + 220312.

It is an arithmetic number, because the mean of its divisors is an integer number (2755523212).

Almost surely, 2^11021680993 is an apocalyptic number.

It is an amenable number.

11021680993 is a deficient number, since it is larger than the sum of its proper divisors (411855).

11021680993 is an equidigital number, since it uses as much as digits as its factorization.

11021680993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 411854.

The product of its (nonzero) digits is 23328, while the sum is 40.

The spelling of 11021680993 in words is "eleven billion, twenty-one million, six hundred eighty thousand, nine hundred ninety-three".