11022430433 has 4 divisors (see below), whose sum is σ = 12597063360. Its totient is φ = 9447797508.

The previous prime is 11022430409. The next prime is 11022430439. The reversal of 11022430433 is 33403422011.

11022430433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11022430433 - 2³² = 6727463137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11022430399 and 11022430408.

It is not an unprimeable number, because it can be changed into a prime (11022430439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 787316453 + ... + 787316466.

It is an arithmetic number, because the mean of its divisors is an integer number (3149265840).

Almost surely, 2^11022430433 is an apocalyptic number.

It is an amenable number.

11022430433 is a deficient number, since it is larger than the sum of its proper divisors (1574632927).

11022430433 is an equidigital number, since it uses as much as digits as its factorization.

11022430433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1574632926.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 11022430433 its reverse (33403422011), we get a palindrome (44425852444).

The spelling of 11022430433 in words is "eleven billion, twenty-two million, four hundred thirty thousand, four hundred thirty-three".