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11022442113 = 33674147371
BaseRepresentation
bin10100100001111110…
…10001111010000001
31001110011200002000210
422100333101322001
5140033221121423
65021425104333
7540101132514
oct122077217201
931404602023
1011022442113
1147469769a1
1221774880a9
1310687844c7
14767c72d7b
15447a23b93
hex290fd1e81

11022442113 has 4 divisors (see below), whose sum is σ = 14696589488. Its totient is φ = 7348294740.

The previous prime is 11022442069. The next prime is 11022442139. The reversal of 11022442113 is 31124422011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11022442113 - 218 = 11022179969 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11022442113.

It is not an unprimeable number, because it can be changed into a prime (11022444113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1837073683 + ... + 1837073688.

It is an arithmetic number, because the mean of its divisors is an integer number (3674147372).

Almost surely, 211022442113 is an apocalyptic number.

It is an amenable number.

11022442113 is a deficient number, since it is larger than the sum of its proper divisors (3674147375).

11022442113 is an equidigital number, since it uses as much as digits as its factorization.

11022442113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3674147374.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 11022442113 its reverse (31124422011), we get a palindrome (42146864124).

The spelling of 11022442113 in words is "eleven billion, twenty-two million, four hundred forty-two thousand, one hundred thirteen".

Divisors: 1 3 3674147371 11022442113