11023433231435 has 8 divisors (see below), whose sum is σ = 13228713919680. Its totient is φ = 8818350557184.

The previous prime is 11023433231383. The next prime is 11023433231441. The reversal of 11023433231435 is 53413233432011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11023433231435 - 2⁴² = 6625386720331 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11023433231395 and 11023433231404.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49380995 + ... + 49603724.

It is an arithmetic number, because the mean of its divisors is an integer number (1653589239960).

Almost surely, 2^{11023433231435} is an apocalyptic number.

11023433231435 is a deficient number, since it is larger than the sum of its proper divisors (2205280688245).

11023433231435 is an equidigital number, since it uses as much as digits as its factorization.

11023433231435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99006997.

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 11023433231435 its reverse (53413233432011), we get a palindrome (64436666663446).

The spelling of 11023433231435 in words is "eleven trillion, twenty-three billion, four hundred thirty-three million, two hundred thirty-one thousand, four hundred thirty-five".