Base | Representation |
---|---|
bin | 10100100010010100… |
… | …10101101111111011 |
3 | 1001110101010101011002 |
4 | 22101022111233323 |
5 | 140034441411220 |
6 | 5022011155215 |
7 | 540134566403 |
oct | 122112255773 |
9 | 31411111132 |
10 | 11025341435 |
11 | 4748577229 |
12 | 2178445b0b |
13 | 106925b094 |
14 | 7683c9803 |
15 | 447de7c75 |
hex | 291295bfb |
11025341435 has 8 divisors (see below), whose sum is σ = 13245500976. Its totient is φ = 8810212320.
The previous prime is 11025341407. The next prime is 11025341443. The reversal of 11025341435 is 53414352011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11025341435 - 218 = 11025079291 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11025341398 and 11025341407.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1252781 + ... + 1261550.
It is an arithmetic number, because the mean of its divisors is an integer number (1655687622).
Almost surely, 211025341435 is an apocalyptic number.
11025341435 is a deficient number, since it is larger than the sum of its proper divisors (2220159541).
11025341435 is an equidigital number, since it uses as much as digits as its factorization.
11025341435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2515213.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 11025341435 its reverse (53414352011), we get a palindrome (64439693446).
The spelling of 11025341435 in words is "eleven billion, twenty-five million, three hundred forty-one thousand, four hundred thirty-five".
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