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11030133113 = 103107088671
BaseRepresentation
bin10100100010111001…
…00111100101111001
31001110201010211002122
422101130213211321
5140042203224423
65022302011025
7540223404326
oct122134474571
931421124078
1011030133113
11475024a29a
122179b76a75
13106a2480ac
14768cb5b4d
154485428c8
hex291727979

11030133113 has 4 divisors (see below), whose sum is σ = 11137221888. Its totient is φ = 10923044340.

The previous prime is 11030133109. The next prime is 11030133133. The reversal of 11030133113 is 31133103011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11030133113 - 22 = 11030133109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11030133091 and 11030133100.

It is not an unprimeable number, because it can be changed into a prime (11030133133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53544233 + ... + 53544438.

It is an arithmetic number, because the mean of its divisors is an integer number (2784305472).

Almost surely, 211030133113 is an apocalyptic number.

It is an amenable number.

11030133113 is a deficient number, since it is larger than the sum of its proper divisors (107088775).

11030133113 is a wasteful number, since it uses less digits than its factorization.

11030133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 107088774.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 11030133113 its reverse (31133103011), we get a palindrome (42163236124).

The spelling of 11030133113 in words is "eleven billion, thirty million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 103 107088671 11030133113