Search a number
-
+
11030320131 = 33676773377
BaseRepresentation
bin10100100010111010…
…10101010000000011
31001110201111022122020
422101131111100003
5140042230221011
65022310012523
7540225113505
oct122135252003
931421438566
1011030320131
114750367856
12217a047143
13106a2b225c
14768d23d75
1544857d006
hex291755403

11030320131 has 4 divisors (see below), whose sum is σ = 14707093512. Its totient is φ = 7353546752.

The previous prime is 11030320123. The next prime is 11030320141. The reversal of 11030320131 is 13102303011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11030320131 - 23 = 11030320123 is a prime.

It is a super-2 number, since 2×110303201312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11030320131.

It is not an unprimeable number, because it can be changed into a prime (11030320111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1838386686 + ... + 1838386691.

It is an arithmetic number, because the mean of its divisors is an integer number (3676773378).

Almost surely, 211030320131 is an apocalyptic number.

11030320131 is a deficient number, since it is larger than the sum of its proper divisors (3676773381).

11030320131 is an equidigital number, since it uses as much as digits as its factorization.

11030320131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3676773380.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11030320131 its reverse (13102303011), we get a palindrome (24132623142).

The spelling of 11030320131 in words is "eleven billion, thirty million, three hundred twenty thousand, one hundred thirty-one".

Divisors: 1 3 3676773377 11030320131