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11031000122003 = 31355838713613
BaseRepresentation
bin1010000010000101101011…
…0110000000001010010011
31110001112221100212001011012
42200201122312000022103
52421212442012401003
635243323235441135
72215651315651631
oct240413266001223
943045840761135
1011031000122003
113573247a9a454
1212a1a6b7561ab
136202aca69a04
142a1c90760351
15141e1ceda8d8
hexa085ad80293

11031000122003 has 4 divisors (see below), whose sum is σ = 11386838835648. Its totient is φ = 10675161408360.

The previous prime is 11031000121997. The next prime is 11031000122027. The reversal of 11031000122003 is 30022100013011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11031000122003 - 234 = 11013820252819 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11031000122063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177919356776 + ... + 177919356837.

It is an arithmetic number, because the mean of its divisors is an integer number (2846709708912).

Almost surely, 211031000122003 is an apocalyptic number.

11031000122003 is a deficient number, since it is larger than the sum of its proper divisors (355838713645).

11031000122003 is an equidigital number, since it uses as much as digits as its factorization.

11031000122003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 355838713644.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 11031000122003 its reverse (30022100013011), we get a palindrome (41053100135014).

The spelling of 11031000122003 in words is "eleven trillion, thirty-one billion, one hundred twenty-two thousand, three".

Divisors: 1 31 355838713613 11031000122003