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1103111310313 = 1636767554051
BaseRepresentation
bin10000000011010110100…
…011101100101111101001
310220110022201112201010001
4100003112203230233221
5121033132443412223
62202432355423001
7142461061300045
oct20032643545751
93813281481101
101103111310313
11395910638531
121599598b4a61
138003b5633ac
143b5687a7025
151da63bd09ad
hex100d68ecbe9

1103111310313 has 4 divisors (see below), whose sum is σ = 1109878864528. Its totient is φ = 1096343756100.

The previous prime is 1103111310281. The next prime is 1103111310397. The reversal of 1103111310313 is 3130131113011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1103111310313 - 25 = 1103111310281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1103111310113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3383776863 + ... + 3383777188.

It is an arithmetic number, because the mean of its divisors is an integer number (277469716132).

Almost surely, 21103111310313 is an apocalyptic number.

It is an amenable number.

1103111310313 is a deficient number, since it is larger than the sum of its proper divisors (6767554215).

1103111310313 is an equidigital number, since it uses as much as digits as its factorization.

1103111310313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6767554214.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1103111310313 its reverse (3130131113011), we get a palindrome (4233242423324).

The spelling of 1103111310313 in words is "one trillion, one hundred three billion, one hundred eleven million, three hundred ten thousand, three hundred thirteen".

Divisors: 1 163 6767554051 1103111310313