110312121113 has 4 divisors (see below), whose sum is σ = 110313646800. Its totient is φ = 110310595428.

The previous prime is 110312121103. The next prime is 110312121167. The reversal of 110312121113 is 311121213011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311121213011 = 7 ⋅44445887573.

It is a cyclic number.

It is not a de Polignac number, because 110312121113 - 2⁸ = 110312120857 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 110312121091 and 110312121100.

It is not an unprimeable number, because it can be changed into a prime (110312121103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 648695 + ... + 800892.

It is an arithmetic number, because the mean of its divisors is an integer number (27578411700).

Almost surely, 2^110312121113 is an apocalyptic number.

It is an amenable number.

110312121113 is a deficient number, since it is larger than the sum of its proper divisors (1525687).

110312121113 is an equidigital number, since it uses as much as digits as its factorization.

110312121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1525686.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 110312121113 its reverse (311121213011), we get a palindrome (421433334124).

The spelling of 110312121113 in words is "one hundred ten billion, three hundred twelve million, one hundred twenty-one thousand, one hundred thirteen".