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11031344344113 = 33677114781371
BaseRepresentation
bin1010000010000110111101…
…0111000110110000110001
31110001120211100120100010020
42200201233113012300301
52421214143123002423
635243421333354053
72215662665542632
oct240415727066061
943046740510106
1011031344344113
113573404328635
1212a1b46a98929
1362033617c032
142a1cc4365889
15141e3d3324e3
hexa086f5c6c31

11031344344113 has 4 divisors (see below), whose sum is σ = 14708459125488. Its totient is φ = 7354229562740.

The previous prime is 11031344344087. The next prime is 11031344344129. The reversal of 11031344344113 is 31144344313011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11031344344113 - 29 = 11031344343601 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11031344344213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1838557390683 + ... + 1838557390688.

It is an arithmetic number, because the mean of its divisors is an integer number (3677114781372).

Almost surely, 211031344344113 is an apocalyptic number.

It is an amenable number.

11031344344113 is a deficient number, since it is larger than the sum of its proper divisors (3677114781375).

11031344344113 is an equidigital number, since it uses as much as digits as its factorization.

11031344344113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3677114781374.

The product of its (nonzero) digits is 20736, while the sum is 33.

Adding to 11031344344113 its reverse (31144344313011), we get a palindrome (42175688657124).

The spelling of 11031344344113 in words is "eleven trillion, thirty-one billion, three hundred forty-four million, three hundred forty-four thousand, one hundred thirteen".

Divisors: 1 3 3677114781371 11031344344113