Base | Representation |
---|---|
bin | 10100100011000111… |
… | …10001111001001001 |
3 | 1001110211200012010120 |
4 | 22101203301321021 |
5 | 140043143312223 |
6 | 5022410133453 |
7 | 540245353242 |
oct | 122143617111 |
9 | 31424605116 |
10 | 11032010313 |
11 | 47513116a5 |
12 | 217a721289 |
13 | 106a75466c |
14 | 769243cc9 |
15 | 4487b3be3 |
hex | 2918f1e49 |
11032010313 has 8 divisors (see below), whose sum is σ = 14709929376. Its totient is φ = 7354382400.
The previous prime is 11032010303. The next prime is 11032010387. The reversal of 11032010313 is 31301023011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-11032010313 is a prime.
It is a super-2 number, since 2×110320103132 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11032010292 and 11032010301.
It is not an unprimeable number, because it can be changed into a prime (11032010303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41073 + ... + 154113.
It is an arithmetic number, because the mean of its divisors is an integer number (1838741172).
Almost surely, 211032010313 is an apocalyptic number.
It is an amenable number.
11032010313 is a deficient number, since it is larger than the sum of its proper divisors (3677919063).
11032010313 is a wasteful number, since it uses less digits than its factorization.
11032010313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145575.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11032010313 its reverse (31301023011), we get a palindrome (42333033324).
The spelling of 11032010313 in words is "eleven billion, thirty-two million, ten thousand, three hundred thirteen".
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